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-35x+x^2=-240
We move all terms to the left:
-35x+x^2-(-240)=0
We add all the numbers together, and all the variables
x^2-35x+240=0
a = 1; b = -35; c = +240;
Δ = b2-4ac
Δ = -352-4·1·240
Δ = 265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{265}}{2*1}=\frac{35-\sqrt{265}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{265}}{2*1}=\frac{35+\sqrt{265}}{2} $
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